Math, asked by rk6345469, 8 months ago

If 4/5 of cistern is filled in 1 minute , how much time will be required to fill the empty cistern? ( Using unitary method )

Answers

Answered by ashy12
2

Answer:

TIME REQUIRED TO FILL THE EMPTY CISTERN = 1 MINUTE 15 SECONDS

Step-by-step explanation:

TIME TAKEN TO FILL 4/5 OF CISTERN = 1 MINUTE = 60 SECONDS

4 PARTS OF THE FULL TIME = 60 SECONDS

1 PART OF THE FULL TIME = 60/4 = 15 SECONDS

TIME TAKEN TO FILL 1/5 OF CISTERN = 15 SECONDS

LETS TAKE THE FULL TIME INTO 5 PARTS

1 PART = 15 SECONDS

SUM OF 5 PARTS (FULL TIME) = 15 + 15 + 15 + 15 + 15 = 5 × 15 = 75 SECONDS

TIME REQUIRED TO FILL THE EMPTY CISTERN = 75 SECONDS = 1 MINUTE 15 SECONDS

I HOPE IT HELPS YOU

MARK AS BRAINLIEST :)

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