if (4,7) is one vector of a rhombus and if the equation of another diagonal
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In a rhombus, the diagonal cut at right angles. The given diagonal is 5x – y + 7 = 0 and (- 4, 7) is not a point on the diagonal. So it will be a point on the other diagonal which is perpendicular to 5x – y + 7 = 0. The equation of a line perpendicular to 5x – y + 7 = 0 will be of the form x + 5y + k = 0. It passes through (-4, 7) ⇒ -4 + 5(7) + k = 0 ⇒ k = -31 So the equation of the other diagonal is x + 5y – 31
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