Math, asked by roseteena468, 16 days ago

if (4/9)^4×(4/9)^-7=(4-9)^2p-1 then find the value of p​

Answers

Answered by harinibharadwaj6
0

Answer:

(4/9)^4 × (4/9)^-7 = ( 4/9)^2p-1

(4/9) ^ 4-7 =(4/9)^2p-1

(4/9)^-3 = (4/9)^2p-1

-3= 2p-1

-3+1 = 2p

-2 = 2p

p= -1

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