Question

if (4/9)^4 × (4/9)^-7 = (4/9)^2x-1, then find the value of x

Answer 1

Answer:

6

Step-by-step explanation:

(4/9)^4×(4/9)^-7 = (4/9)^2x-1

[a^m × a^n = a^(m+n)]

(4/9)^(4+7) = (4/9)^2x-1

(4/9)^11 = (4/9)^2x-1

In an equation, when bases are are same, powers get equated.

11 = 2x-1

2x = 11+1

2x = 12

x = 6