Question

if 4^α=9^b=36^c then prove that 2a + 3b=6abc

Answer 1

hey mate,

$\frac{2a}{6abc} + \frac{3b}{6ab} = \frac{6abc}{6abc} \\ \\ = \frac{1}{3bc} + \frac{1}{3ab} = 1 \\ \\ = 2a + 3b = 6abc$
I hope this helps you!
@vaibhav246