If 4, a , b, c , 28 are in AP then c= ? *
Answers
Step-by-step explanation:
Given :-
4, a , b, c , 28 are in AP
To find:-
Find the value of c ?
Solution :-
General Method:-
Given that :
4, a , b, c , 28 are in AP
First term ( a ) = 4
Fifth term (a 5)= 28
We know that
nth term of an AP is an = a+(n-1) d
=> a 5 = a+(5-1)d
=> a 5 = a+4d
=> a+4d = 28
=> 4+4d = 28
=> 4d = 28-4
=> 4d = 24
=> d = 24/4
=> d = 6
Common difference = 6
Now,
c is the fourth term
=> a 4 = a+3d
=> c = 4+3(6)
=> c = 4+18
=>c = 22
Therefore, c = 22
Alternative Method:-
Given that
4, a , b, c , 28 are in AP
We know that
If 'n' AM's are between a and b then d = (b-a)/(n+1)
We have , a = 4, b = 28 ,n = 3
Since a,b,c are between 4 and 28
=> d = (28-4)/(3+1)
=>d = 24/4
=> d = 6
c is the fourth term
=> a 4 = a+3d
=> c = 4+3(6)
=> c = 4+18
=>c = 22
Therefore, c = 22
Answer:-
The value of c for the given problem is 22
Used formulae:-
- nth term of an AP is an = a+(n-1) d
- If 'n' AM's are between a and b then d = (b-a)/(n+1)
- a = First term
- b = last term
- d = Common difference
- n = Number of terms
- AM = Arithmetic Mean
- AP = Arithmetic Progression
Answer:
The value of C will be 22..
Step-by-step explanation:
the secret to finding the value is hide in a common difference ..Once you find a common difference it will be a piece of Cake..
