Question

if (4,a) is solution of 2x + 3y = 23 then find the value of a​

Answer 1

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Polynomial: 2x+3y=23

Therefore, 2x+3y-23=0

Co-efficients: a=2, b=3, c=(-23)

Zeroes= $\alpha = 4\\\beta=a$

$\alpha \beta =\frac{c}{a} \\\alpha\beta = 4a--------------(1)\\\alpha \beta = \frac{23}{2} --------------(2)$

Equate 1 and 2

$4a=\frac{23}{2}\\\\ a=\frac{23}{2} *\frac{1}{4} \\a=\frac{23}{8}$

Therefore the second zero is 23/8

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Answer 2

Answer:

THIS IS YOUR ANSWER

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Polynomial: 2x+3y=23

Therefore, 2x+3y-23=0

Co-efficients: a=2, b=3, c=(-23)

Zeroes= \begin{gathered}\alpha = 4\\\beta=a\\\end{gathered}

α=4

β=a

\begin{gathered}\alpha \beta =\frac{c}{a} \\\alpha\beta = 4a--------------(1)\\\alpha \beta = \frac{23}{2} --------------(2)\\\end{gathered}

αβ=

a

c

αβ=4a−−−−−−−−−−−−−−(1)

αβ=

2

23

−−−−−−−−−−−−−−(2)

Equate 1 and 2

\begin{gathered}4a=\frac{23}{2}\\\\ a=\frac{23}{2} *\frac{1}{4} \\a=\frac{23}{8}\end{gathered}

4a=

2

23

a=

2

23

∗

4

1

a=

8

23

Therefore the second zero is 23/8

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