Question

If  4 and its negative are the two zeros of polynomial , then other two zeros are x² - 17x² + 16​

Answer 1

Ans:- Given:-

P(x):- x² - 17x² + 16

Zeroes:- 4 and -4

Now,

x² - 16 = (x + 4)(x - 4)

now, divide the P(x) by x² - 16 to obtain other two zeroes.

(x⁴ - 17x² + 16) ÷ (x² - 16)

(x⁴ - 16x² - x² + 16) ÷(x² - 16)

(x²(x² - 16) -1(x² - 16)) ÷ (x² - 16)

(x² - 1) = (x + 1)(x - 1)

so, other two zeroes are 1 and -1.

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