If 4 children or 2 women can work equally as one man, and 10 children 8 ladies and 8 men can reap 14 fields in 7 days, how many children are needed to reap the 7 fields in the same time?
Answers
Given : 4 children or 2 women can work equally as one man, and 10 children 8 ladies and 8 men can reap 14 fields in 7 days,
To Find : how many children are needed to reap the 7 fields in the same time?
Solution:
4 children or 2 women can work equally as one man
Let say one man do work in 1 day = 4P
2 women can do work in 1 day = 4P
=> 1 women can do work in 1 day = 4P/2 = 2P
4 children can do work in 1 day = 4P
=> 1 children can do work in 1 day = 4P/4 = P
10 children 8 ladies and 8 men can reap 14 fields in 7 days,
=> 10 children 8 ladies and 8 men can reap 14/7 fields in 7/7 days
=> 10 children 8 ladies and 8 men can reap 2 fields in 1 days
work done by 10 children 8 ladies and 8 men in 1 days = 10 *P + 8 * 2P + 8 * 4P
= 10P + 16P + 32P
= 58P
58P work needed to reap 2 field in 1 day
=> 58P/2 work needed to reap 2/2 field in 1 day
=> 29P work needed to reap 1 field in 1 day
=> 29 P work needed to reap 7 field in 7 day
Number of Children required = 29
29 children are needed to reap the 7 fields in the same time
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Answer:
4c = 2w =1m
2c =1w
10c =8w =8m -- 14fields in 7days
|. |. |.
10c + 16c + 32c =58 children
58×7/14 = C×7/7
=Ans 29