If 4 cos 0 = 11 sin 0, find the value of
11 cos0-7 sine\11 cos 0+7 sin0
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2
Answer:
93/149
Step-by-step explanation:
4 cosA = 11 sinA
sinA /cosA = 4/11 => tanA = 4/11 = p/b
h = √(11^2+4^2) = √137
(11 cosA - 7 sinA)/(11cosA + 7sinA)
(11×11/√137 -7×4/√137)/(11×11/√137 + 7×4/√137)
= (121-28)/(121+28) = 93/149
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