Math, asked by ghoshsujal457, 7 months ago

If 4 cos 0 = 11 sin 0, find the value of
11 cos0-7 sine\11 cos 0+7 sin0​

Answers

Answered by TheLostMonk
2

Answer:

93/149

Step-by-step explanation:

4 cosA = 11 sinA

sinA /cosA = 4/11 => tanA = 4/11 = p/b

h = √(11^2+4^2) = √137

(11 cosA - 7 sinA)/(11cosA + 7sinA)

(11×11/√137 -7×4/√137)/(11×11/√137 + 7×4/√137)

= (121-28)/(121+28) = 93/149

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