Question

if 4 cos^2A -3=0 and 0° ≤ A ≤ 90°, find i angle a ii cos 3 a iii tan^2 A + cos ^2 A​

Answer 1

4cos²A-3=0

cos²A = 3/4

cosA=√3/2 = cos 30

i)Angle A= 30

ii)cos 3×30 = cos 90 =0

iii)tan²30+ cos²30

=(1/√3)²+(√3/2)²

=1/3 + 3/4

= 4+9

12

= 13/12

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