Question

if 4 cos^2a -3=0 and < a < 90°, find i angle a ii cos 3 a iii tan^2 a + cos ^2 a​

Answer 1

Answer:

4 cos²A -3= 0

cos²A = 3/4

cosA = √ 3/2 = cos 30⁰

i) angle A = 30⁰

ii) cos 3A = cos 3× 30

cos 90⁰= 0

iii) tan² 30 + cos²30

( 1/√3)² + (√3/2)²

1/3 + 3/4

4+9

12

=13

12

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