Math, asked by bisoyibhabani, 7 months ago

. If 4 cos2 A-3 = 0 and 0° <- A <- 90°;
find : (i) angle A (ii) cos 3A
(iii) tan? A + cos? A​

Answers

Answered by tusharagar5217
10

Step-by-step explanation:

4cos²A=3

cos²A=3/4

cosA=√3/2

since cos 30°=√3/2

therefore angleA= 30°

cos 3A= cos90°

therefore, cos3A=0

tan²A+cos²A=sin²A/cos²A+cos²A

by putting the value of A we get,

1/4/3/4+3/4=1/3+3/4=7/12

Answered by vidyaarun289
1

Answer:

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