If 4 Cos21 - 1=0, then the value of Sec is
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sin 2x = 1 and cos x = 0 ) which is not possible for any value of x . Since 2 tan ' x – 5 sec x = 1 = 2 ( secʻx - 1 ) – 5sec x – 1 = 0 = 2sec ? x – 5 sec x – 3 = 0 = ( 2sec x + 1 ) ( sec x – 3 ) = 0 ) But sec x | 21 ( by definition ) So , sec x = 3.
Explanation:
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