If 4 cot θ = 3 then find the value of of tan θ + cot θ
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Answered by
1
4cotθ = 3
⇒cot θ = 3/4
⇒tan θ = 4/3
⇒cotθ + tanθ = 3/4 + 4/3
⇒cotθ + tanθ = 25/12
⇒cot θ = 3/4
⇒tan θ = 4/3
⇒cotθ + tanθ = 3/4 + 4/3
⇒cotθ + tanθ = 25/12
Answered by
0
cot∅= 3/4= base/perpendicular
By Pythagoras Theorem
(H)²= (P)²+(B)²
(H)²= (4)²+(3)²
(H)²= 16+9
(H)²= 25
H= 5
tan∅= perpendicular/base= 4/3
cot∅= base/perpendicular= 3/4
tan∅+cot∅= 4/3+3/4= 16+9/12
25/12.
By Pythagoras Theorem
(H)²= (P)²+(B)²
(H)²= (4)²+(3)²
(H)²= 16+9
(H)²= 25
H= 5
tan∅= perpendicular/base= 4/3
cot∅= base/perpendicular= 3/4
tan∅+cot∅= 4/3+3/4= 16+9/12
25/12.
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