Question

If 4 cot A = 3, then find
sin A+cos A divided by

sin A-Cos A
('A'is acute)​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

CotA = 3/4 = आधार/लम्ब

कर्ण = √(A)²+(L)² = √(9+16) = √25 = 5

SinA = 4/5 , CosA = 3/5

SinA+CosA/SinA-CosA

(7/5)/(1/5)

7/1 = 7