If 4 cot theta - 3 = 0 find cot² theta - cosec² theta.
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Answer:
Step-by-step explanation:
cot theta = 4/3
therefore you get b(base) and p(perpendicular), so find h(hypotenuse) by using h = √p2 + b2
by this you can find h (hypotenuse).
So, cot2 theta = (4/3)2 = 16/9, and,
cosec2 theta = h/p = (5/3)2 = 25/9.
Now solve your question
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