Question

if 4 cot theta is equals to 3 show that sin theta minus cos theta upon sin theta + cos theta is equals to 1 upon 7​

Answer 1

Answer:

$\cot( \alpha ) = \frac{3}{4}$

$\sin( \alpha ) = \frac{4}{5} \: \: and \: \: \: \cos( \alpha ) = \frac{3}{5}$

now,

$\frac{ \sin( \alpha ) - \cos( \alpha ) }{ \sin( \alpha ) + \cos( \alpha ) } = \frac{ \frac{4}{5} - \frac{3}{5} }{ \frac{4}{5} + \frac{3}{5} } = \frac{1}{5} \div \frac{7}{5} = \frac{1}{7}$

Proved.

Answer 2

Answer:

hope this may help you..

thanks