If 4 dice tossed together , what is the probability of sum of these dice will be exactly 20?
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As double dies are thrown therefore the total outcomes become 36.The outcomes are as following
(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)
(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)
(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)
(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)
(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)
(6,1),(6,2),(6,3),(6,4),(6,5),(6,6).
1) Now to have a doublet we should found same numbers between brackets such as (1,1),(2,2),(3,3),(4,4),(5,5),(6,6)
Therefore the favourable cases are 6
Probability =
2)We should count outcomes having sum of 10 such that (4,6),(5,5)(6,4).So favourable outcomes are 3
Probability =
Hope this would have been clear to you buddy. Please mark as the brainliest.
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(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)
(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)
(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)
(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)
(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)
(6,1),(6,2),(6,3),(6,4),(6,5),(6,6).
1) Now to have a doublet we should found same numbers between brackets such as (1,1),(2,2),(3,3),(4,4),(5,5),(6,6)
Therefore the favourable cases are 6
Probability =
2)We should count outcomes having sum of 10 such that (4,6),(5,5)(6,4).So favourable outcomes are 3
Probability =
Hope this would have been clear to you buddy. Please mark as the brainliest.
Read more on Brainly.in - https://brainly.in/question/3093170#readmore
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