Question

If 4 g molecule of H2 is present in a two-litre
container, the active mass will be​

Answer 1

Answer:

Mass of hydrogen =4 g

Molecular mass of hydrogen =2

Volume of the flask =2 litre

Active mass of hydrogen = 2×2=4

=1 mol L −1

Mass of HI=128 g

Molecular mass of HI=128

Volume of the flask =2 litre

Active mass of hydrogen iodide = 128/2×128

=0.5 mol L −1