if 4 g of Noah dissolve in 36 g of h20 calculate mole fraction of each component in the solution. also determine molarity of solution
Answers
Answer:
Mole fraction of H2O
= No.of moles of H2O/Total No.of moles (H2O + NaOH)
No. of moles of H2O = 36/18 = 2 moles
No. of moles NaOH = 4/40 = 0.1 mol
Total number of moles = 2+0.1 = 2.1
Mole fraction of H2O = 2/2.1 = 0.952
Mole fraction of NaOH = 0.1/2.1 = 0.048
Mass of solution
= Mass of H2O + Mass of NaOH = 36 + 4 = 40 g
Volume of solution = 40/1 = 40 mL
Molarity = No.of moles of solute/Volume of solution in L
= 0.1/0.04L = 2.5M
Explanation:
BILLI DIDI MEIN 7 MAI PADHTA HUN
MERE KO TO AISA KUCHH NAHIN PATA BUS GOO GLE SE CHAP DIYA LOL
MARK ME BRAINLIEST PLS
Mole fraction of H2O
= No.of moles of H2O/Total No.of moles (H2O + NaOH)
No. of moles of H2O = 36/18 = 2 moles
No. of moles NaOH = 4/40 = 0.1 mol
Total number of moles = 2+0.1 = 2.1
Mole fraction of H2O = 2/2.1 = 0.952
Mole fraction of NaOH = 0.1/2.1 = 0.048
Mass of solution
= Mass of H2O + Mass of NaOH = 36 + 4 = 40 g
Volume of solution = 40/1 = 40 mL
Molarity = No.of moles of solute/Volume of solution in L
= 0.1/0.04L = 2.5M