Question

If - 4 is a common root of 2x^+px + 8 =0 and p (x2 + x) + k = 0, then find the value of k?​

Answer 1

Answer:

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Answer 2

Answer:

Given: -4 is a common zero of 2x² + px + 8 & p(x² + x) + k

So,

2(-2)² + p(-2) + 8 = 0

=> 2(4) - 2p + 8 = 0

=> 2p = 8 + 8

=> 2p = 16

=> p = 16/2 = 8

Now, we will do the same for the second equation, but substitute in the value of p, to find k.

=> p((-2)² + (-2)) + k = 0

=> k = - (8)(4 - 2)

=> k = -8(2)

=> k = -16

Therefore, k = -16