Question

if -4 is a root of a quadratic eqn 2 x^2+px-12=0 find the value of p​

Answer 1

p(x)=2x^2+px-12

p(-4)=0

2(-4)^2+p(-4)-12=0

32-4p-12=0

20=4p

p=5

Answer 2

Answer

p(x) = 2x^2 + px- 12 = 0

p(-4)= 2(-4)^2 + (-4)p - 12 = 0

=> 32 - 4p - 12 = 0

=> 4p = 20

=> p = 5