if -4 is a root of equation X ^2 + px - 4 is equals to zero and equation X ^2- 3 x + K is equal to zero has equal roots find the value of P and K
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rohanharolikar:
in 1st equation it's x² + px - 4 not x² - px - 4
its okkk
its okkk dear
hmmmm
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x²+px-4 = 0
-4 is a root
therefore
(-4)²+(-4)p-4 = 0
16-4p = 4
12 = 4p
p = 3
x²-3x+k = 0
roots are equal
therefore discriminant = 0
b²-4ac = 0
(-3)²-4(1)(k) = 0
9 = 4k
k = 9/4
-4 is a root
therefore
(-4)²+(-4)p-4 = 0
16-4p = 4
12 = 4p
p = 3
x²-3x+k = 0
roots are equal
therefore discriminant = 0
b²-4ac = 0
(-3)²-4(1)(k) = 0
9 = 4k
k = 9/4
thanks for selecting as brainliest
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