Question

if -4 is a root of quadratic equation x square + px - 4 = 0 and x square + px + k = 0 has equal roots, find the value of k​??​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

-4 is root of

${x}^{2} + px - 4 = 0$

so - 4 will satisfy this eq.

$( - 4) {}^{2} - 4p - 4 = 0$

$16 - 4 = 4p$

$p = 3$

putting value of P in 2nd equation..

${x}^{2} + 3x + k = 0$

it has equal roots, so it's discriminant = 0

${3}^{2} - 4k = 0$

$4k = 9$

$k = \frac{9}{4} \: \: ans.$