Question

If -4 is a root of rhe equation x^2 + px-4 =0 and the equation x^2 + px +q =0 has equal roots , final the values of p and q.

Answer 1

$here \: x = - 4 \\ and \: {x}^{2} + px + q = 0 \\ {( - 4)}^{2} + p( - 4) - 4 = 0$

$16 - 4p - 4 = 0 \\ - 4p = - 12 \\ p = 3$

substituting the value of p in second equation we get,

${x}^{2} + 3x + q = 0$

here Discriminant = 0

${b}^{2} - 4ac = 0$

${3}^{2} - 4(1)(q) = 0 \\ 9 - 4q = 0 \\ - 4q = - 9 \\ q = \frac{9}{4}$

$mark \: as \: brainlist$

Answer 2

plz refer to this attachment