If 4 is a root of the equatien px^2 -54x+40 = 0
find the value of p and also find the other root?
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Step-by-step explanation:
Put x = 4
= p (4)² - 54 X 4 +40 =0
= 16p - 216 + 40 = 0
= 16p - 176= 0
= 16p = 176
= p = 176/16
= p = 11
Now, put p = 11
= px² - 54x +40 =0
= 11x² -54x +40 = 0
By splitting the middle term
= 11x² - 44x - 10x +40 =0
= 11x ( x-4) -10(x-4) =0
= 11x-10 =0 , x-4=0
= 11x=10 , x= 4
= x = 10/11
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