Question

If -4 is a root of the equation x^2 +px -4=0 and the equation x^2+px+q=0 has equal roots, find the values of p and q. (here x^2 means x squared)​

Answer 1

Answer:

p=3,q=-4

Step-by-step explanation:

x=-4 (given)

x2+px-4=0

(-4)2+p(-4)-4=0

16-4p-4=0

12-4p=0

-4p=-12

p=3

If the equation has equal roots then it is equal to 0

x2+px+q=0

(-4)2+3(-4)+q=0

16-12+q=0

4+q=0

q=-4

I hope this answer may help you