Question

If -4 is a root of the equation X square + PX - 4 equal to zero and the equation X square + PX + Q equal to zero has equal roots then find the values of P and Q

Answer 1

Answer:

p = 3, q = -4.

Step-by-step explanation:

x^2+px-4=0=x^2+px+q

=> x^2-x^2+px-px-4=q

=> q = - 4

As they both have equal roots thus -4 is the only root of the equation.

Therefore,

(-4)^2+p(-4)-4=0

=> 16- 4p- 4 = 0

=> 12 = 4p

=> p= 12/4

=> p=3.