Question

If -4 is a root of the equation x2 + px -4 = 0 and the equation x2 + px + q = 0 has real roots find the value of p and q ?

Answer 1

Answer:

$p = 3 \: \: \: and \: \: \: q \geqslant \frac{9}{4}$

Step-by-step explanation:

${x}^{2} + px - 4 = 0 \\ put \: x = - 4 \\ 16 - 4p - 4 = 0 \\ - 4p + 12 = 0 \\ 4p = 12 \\ p = 3 \\ \\ \\ {x}^{2} + px + q = 0 \\ put \: p = 3 \\ {x }^{2} + 3x + q = 0 \\ for \: real \: roots \\ {3}^{2} - 4q \geqslant 0 \\ q \geqslant \frac{9}{4}$

Answer 2

Answer:

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