Question

If -4 is a root of the quadratic equation 2x^2+px-12=0.Find the value of p

Answer 1

firstly put the value of f(x)=-4 in the equation
it will become 2(-4)^2+p(-4)-12=0
= 32-4p-12=0
=20-4p=0
=20=4p
=p=5