if -4 is a zero of a polynomial x2-x-(2+2k), then value of k is
Answers
Answered by
0
Answer:
x2 – x – (2k + 2) = 0
(-4)^2 – (-4) – 2k – 2 = 0
16 + 4 – 2k – 2 = 0
-2k + 18 = 0
k = 9
The value of k is 9.
Step-by-step explanation:
hope this helped ya please mark me the brainliest
Answered by
0
Answer:
k= 9
Step-by-step explanation:
If -4 is substituted in the equation, the equation equals to zero.
Therefore, x²-x-(2+2k)=0
(-4)²-(-4)-2-2k=0
18-2k=0
k= -18/-2
k= 9
Hope it helps!
Similar questions