Math, asked by sadhanaasuresh, 2 months ago

if -4 is a zero of a polynomial x2-x-(2+2k), then value of k is

Answers

Answered by palakjoshi18
0

Answer:

x2 – x – (2k + 2) = 0

(-4)^2 – (-4) – 2k – 2 = 0

16 + 4 – 2k – 2 = 0

-2k + 18 = 0

k = 9

The value of k is 9.

Step-by-step explanation:

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Answered by syedaumaizaunsa07
0

Answer:

k= 9

Step-by-step explanation:

If -4 is substituted in the equation, the equation equals to zero.

Therefore, x²-x-(2+2k)=0

(-4)²-(-4)-2-2k=0

18-2k=0

k= -18/-2

k= 9

Hope it helps!

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