if -4 is a zero of polynomial:p(x)=x^2+11x+k,then find k
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Answered by
10
since -4 is a zero of p(x)
p(-4)=-4^2+11(-4)+k=0
16-44+k=0
-28+k=0
k=28
Therefore the value of k is 28
p(-4)=-4^2+11(-4)+k=0
16-44+k=0
-28+k=0
k=28
Therefore the value of k is 28
Answered by
8
hola!
Given :-
p(x) = x² + 11x + k n' -4 is Zero of the polynomial.
p(-4) = x² + 11x + k = 0
x² + 11x + k = 0
(-4)² + 11(-4) + k = 0
16 - 44 + k = 0
k - 28 = 0
k = 28
Hence, The required answer is:- k = 28
hope it helps! :)
Given :-
p(x) = x² + 11x + k n' -4 is Zero of the polynomial.
p(-4) = x² + 11x + k = 0
x² + 11x + k = 0
(-4)² + 11(-4) + k = 0
16 - 44 + k = 0
k - 28 = 0
k = 28
Hence, The required answer is:- k = 28
hope it helps! :)
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