if (-4) is a zero of polynomial x^2-x-(2+k), then find the value of k
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Answered by
5
Heya !!
X = -4
P( x ) = X² - X - ( 2 + K )
P (-4) = (-4)² - (-4) - ( 2 + K )
=> 16 + 4 - 2 - k = 0
=> - k + 18 = 0
=> - k = -18
=> k = 18
X = -4
P( x ) = X² - X - ( 2 + K )
P (-4) = (-4)² - (-4) - ( 2 + K )
=> 16 + 4 - 2 - k = 0
=> - k + 18 = 0
=> - k = -18
=> k = 18
Answered by
1
Hey !
-4 Is a zero of the polynomial x²-x-(2+k).
Putting x = -4 in p(x ).
P( x ) = X² - X - ( 2 + K )
P (-4) = (-4)² - (-4) - ( 2 + K )
16 + 4 - 2 - k = 0
- k + 18 = 0
k = 18.
-4 Is a zero of the polynomial x²-x-(2+k).
Putting x = -4 in p(x ).
P( x ) = X² - X - ( 2 + K )
P (-4) = (-4)² - (-4) - ( 2 + K )
16 + 4 - 2 - k = 0
- k + 18 = 0
k = 18.
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