Question

)If -4 is a zero of the p(x)=x²+x-(2K+2) then k=?

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Answer 1

$p(x) = ( - 4) {}^{2} + ( - 4) - 2k - 2 \\ 0 = 16 - 4 - 2k - 2 \\ 0 = 10 - 2k \\ k = 10 \div 2 = 5$

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Answer 2

Answer:

p(x)=(−4)

2

+(−4)−2k−2

0=16−4−2k−2

0=10−2k

k=10÷2=5

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Step-by-step explanation:

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