if -4 is a zero of the polynomial p(x)=x²+11x+k,find the value of k
Answers
Answered by
11
Dear friend,
Here's your answer...
x = - 4
By using Factor Theorem,
p(x) = x² + 11x + k = 0
p(- 4) = (-4)² + 11 × (-4) + k = 0
= 16 - 44 + k = 0
= -28 + k = 0
= k = 28
**Hope it helps you !!
Here's your answer...
x = - 4
By using Factor Theorem,
p(x) = x² + 11x + k = 0
p(- 4) = (-4)² + 11 × (-4) + k = 0
= 16 - 44 + k = 0
= -28 + k = 0
= k = 28
**Hope it helps you !!
Answered by
8
Given :
P(x) = x²+11x+k
To Find:
Value of k
Solution :
Given that -4 is the zero of polynomial p(x)
Putting x = -4
p(x) = x²+11x+k
p(-4) = (-4)²+11(-4)+k
16-44+k = 0
-28+k = 0
k = 28
P(x) = x²+11x+k
To Find:
Value of k
Solution :
Given that -4 is the zero of polynomial p(x)
Putting x = -4
p(x) = x²+11x+k
p(-4) = (-4)²+11(-4)+k
16-44+k = 0
-28+k = 0
k = 28
Similar questions