Question

If -4 is a zero of the polynomial x^2- x-(2+2K),
then find the value of k.​

Answer 1

Answer:

if we substitute -4 in place of x we should get 0

Answer 2

$\huge\bold{\mathtt{\purple{A}\red{N}\purple{S}\red{W}\purple{E}\red{R}\purple{:}\red{-}}}$

GIVEN ➡ -4 is a zero of the polynomial x² - x - (2+2k)

TO FIND ➡ the value of k

»» p(x) ➡ x² -x -(2+2k) =0

• from given { -4 is a zero of the polynomial }

»» p(-4) ➡ (-4)² -(-4) -(2+2k) =0

»» p(-4) ➡ 16 +4 -2 -2k =0

»» p(-4) ➡ 20-2-2k = 0

»» p(-4) ➡ 18-2k = 0

»» p(-4) ➡ -2k = -18

»» p(-4) ➡ k = -18/-2

»» p(-4) ➡ k = 9

${\bf{\blue{\fbox{\underline{\color{red}{so, \: k \: = \: 9}}}}}}$