Question

If –4 is a zero of the polynomial
x²–x–(2+2k), then find the value of k.

The best and correct answer would surely marked as brainliest, while unwanted would be reported immediately.​

Answer 1

Answer:

hey mate,, here is your answer..

Step-by-step explanation:

f(x) = x²–x–(2+2k)

:– x = -4

:– f(-4) = (-4)^2 - (-4) - 2 - 2k

0 = 16 + 8 - 2 -2k

0 = 24 - 2 - 2k

0 = 22 - 2k

2k = 22

k = 22/2

:– k = 11

hope it helps u frnd !

Answer 2

Answer:

k = 9

Step-by-step explanation:

p(x) = x² - x - (2+2k)

Putting x = -4,

p(-4) = (-4)² - (-4) - 2 - 2k

0 = 16 + 4 - 2 - 2k

0 = 18 - 2k

2k = 18

k = 18/2

k = 9

Hope it helps!