Question

If -4 is a zero of the polynomial x2-x-(2+2k), then find the value of k.

Answer 1

Answer:

             k = 9

Step-by-step explanation:

Given that,

-4 is a zero of the polynomial. Then,

p(-4) = x^2 - x - 2 - 2k = 0

=> (-4)^2 - (-4) - 2 - 2k = 0

=> 16 + 4 - 2 -2k = 0

=> 2k = 20-2

=> 2k = 18

=> k = 18/2

=> k = 9

Answer 2

Answer:

The value of $k=9$

Step-by-step explanation:

It is given that the zero of polynomial is $-4$.

The given polynomial is $x^{2} -x-(2+2k)=0$

Zero of polynomial means that the value of $x$ satisfying the equation.

A polynomial refers to an expression that consists of indeterminates and coefficients which involves only the operations of addition, subtraction, multiplication, and non-negative integer exponentiation of variables.

We need to determine value of $k$

It can be done by substituting the value of $x=-4$

$(-4)^{2} -(-4)-(2+2k)=0$

$16+4-2-2k=0$

$18-2k=0$

$18=2k$

$k=9$

The value of $k$ is $9$

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