Question

If - 4 is a zero of the
polynomial x2- x- (2+2k),
then value of K is :​

Answer 1

Answer:

k=9

Step-by-step explanation:

$f(-4)=x^{2} -x-(2+2k)=0\\(-4)^{2}-(-4)-2-2k=0\\16+4-2-2k=0\\18=2k\\\frac{2k}{2}=\frac{18}{2}\\k=9$

Answer 2

Answer:

Value of k is 9

hope this answer helps you.