Question

If 4 is added to the product of 2 consecutive multiples of 4 gives 324.if first number is 'x' then find second number

Answer 1

Let the numbers be x and x+4

By the given conditions,

4 + x(x+4) = 324

x²+4x = 320

x²+4x-320 = 0

x = (-b±√D)/2a

D = b²-4ac

D = 16 - 4*1*-320

D = 16+1280 = 1296

√D = √1296 = 36

Hence

x = (-b±√D)/2a

x = (-4±36)/2

Hence

x = (36-4)/2                                x = (-36-4)/2

x = 32/2                                      x = -40/2

x = 16                                           x = -20

Hence the multiples are

16 and 20 or

-16 and -20

Hope this is helpful to you

Pls mark as brainliest

Follow me and I'll follow you back

Answer 2

Let the 1st no. be x

Therefore second no. is x + 4

Now , we know that ,

x(x+4) + 4 = 324

x^2 + 4x = 320

x ^ 2 + 4x - 320 = 0

x ^2 + 20x -16x -320 =0

x ( x + 20 ) - 16 ( x + 20) = 0

( x - 16 ) ( x + 20 ) = 0

Thus , we have

x = 16 , 20

Therefore the two multiples are 16 and 20

Mark me brainliest pleaseeeeeeee

Don't forget to follow me

Make my answer great