Question

If 4 is less than x is less than 8 then the value of 12x-x^2-32 is

Pls answer fast!

Hint: It is a question from quadratic equation.

Who will answer fast I will mark as brainleast and follow them.



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Answer 1

Concept:

The polynomial equations of degree two in one variable of type f(x) = ax2 + bx + c = 0 and with a, b, c, and R R and a 0 are known as quadratic equations. It is a quadratic equation in its general form, where "a" stands for the leading coefficient and "c" for the absolute term of f(x).

Given information:

The following information is given:

$4 < x < 8\\12x-x^{2} -32$

To find:

Find the value of $x$.

Solution:

The following information is given:

$4 < x < 8\\12x-x^{2} -32$

Now,

$12x-x^{2} -32 = -(x^{2} -12x+32)$

                      $= -(x^{2} -4x-8x+32)\\=-(x(x-4)-8(x-4))\\=-((x-4)(x-8))$

The value of $x$ lies between $4$ and $8$.

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