If 4' is one of the zeroes of p(x) = x2.+kx - 8, then the value of k
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Answered by
20
Answer:
p(X)=X2+kx-8
p(4)=16+4k-8
8-16=4k
-8=4k
-2=k
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may be 2 by solving
u put x =4
x^2+kx-8
4^2+k*4-8
16+(-8) +k*4
8 +k*4
k =8\4
=2 ans
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