Question

If 4' is one of the zeroes of p(x) = x2.+kx - 8, then the value of k



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Answer 1

Answer:

p(X)=X2+kx-8

p(4)=16+4k-8

8-16=4k

-8=4k

-2=k

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Answer 2

Answer:

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may be 2 by solving

u put x =4

x^2+kx-8

4^2+k*4-8

16+(-8) +k*4

8 +k*4

k =8\4

=2 ans