Question

if -4 is one root of the equation X square + kx - 8 is equal to zero then find the value of k ​

Answer 1

Answer:

Value of k is 2 .

Step-by-step explanation:

let ,

X = -4

p(X) =

$p(x) = x ^{2} + kx - 8 = 0$

$p( - 4) = ( - 4) ^{2} + k( - 4) - 8 = 0 \\ \: \: \: \: = 16 - 4k - 8 = 0 \\ \: \: \: \: = 8 = 4k \\ \: \: \: \: \: = k = \frac{8}{4} \\ \: \: \: \: \: = k = 2$

Answer 2

$\large{\underline{\underline{\mathfrak{\green{\sf{Answer-}}}}}}$.

$\large{\underline{\underline{\mathfrak{\green{\sf{Given \:here\:equations}}}}}}$.

✴x² + kx -8.

➡If -4 , is a root of this equations .

So, x=-4, exits this equations .

➡So, keep X=-4, in place of x.

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$\implies\:2^2+2*k-8\:=\:0$.

$\implies\:4+2k-8\:=\:0$.

$\implies\:2k\:=\:4$ .

$\implies\:k\:=\frac{4}{2}$. $\implies\:k\:=\:2$

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