If 4 is the root of quadratic equation x²+ax-8=0 then a=
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4^2+4a-8=0
16+4a-8=0
4a=-8
a=-2
16+4a-8=0
4a=-8
a=-2
hemanth2261:
thank you
Answered by
2
putting value of x in given eqn
we get
4^2+a4-8=0
16+4a-8=0
4a=8-16
a=-8/4=-2
we get
4^2+a4-8=0
16+4a-8=0
4a=8-16
a=-8/4=-2
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