Question

if -4 is the root of the equation Xsquare +px-4=0 then the value of 0 is?​

Answer 1

Answer:

p = 3

Step-by-step explanation:

${x}^{2} + px - 4 = 0 \\ x = - 4 \\ {( - 4)}^{2} + p( - 4) - 4 = 0 \\ 16 - 4p - 4 = 0 \\ 12 - 4p = 0 \\ - 4p = - 12 \\ p = \frac{ - 12}{ - 4} \\ p = 3$

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