if -4 is the root of the quadratic equation x^2+kx+-4 = 0 and the quadratic equation x^2+px+k = 0 has equal roots. find the value of k and p
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Hi friend your answer is that.
Zero of the equation = -4
we will put the value of zero in the first equation.
xsq.+kx-4
4sq. + 4k -4 = 0
16 + 4k -4 =0
4k +12=0
4k = -12
k= -12/4
k = -3.ans.
now we will put the value of K in the second equation.
xsq. +px +k
4sq. + 4p +(-3) = 0
16 +4p -3 =0
4p + 13 = 0
4p = -13
p = -13/4 answer.
Then.
K = -3. & P = -13/4.
it will help.
Zero of the equation = -4
we will put the value of zero in the first equation.
xsq.+kx-4
4sq. + 4k -4 = 0
16 + 4k -4 =0
4k +12=0
4k = -12
k= -12/4
k = -3.ans.
now we will put the value of K in the second equation.
xsq. +px +k
4sq. + 4p +(-3) = 0
16 +4p -3 =0
4p + 13 = 0
4p = -13
p = -13/4 answer.
Then.
K = -3. & P = -13/4.
it will help.
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