If -4 is the zero of polynomial xsquare -x-(2+2k)then find value of k.
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Answered by
4
Put x=-4
(-4)^2-(-4)-(2+2k)=0
16+4-2-2k=0
18-2k=0
2k=18
K=9
(-4)^2-(-4)-(2+2k)=0
16+4-2-2k=0
18-2k=0
2k=18
K=9
Answered by
1
xquare - x - 2 + 2k
x = (-4)
(-4)square - (-4) - 2 + 2k = 0 (By factor theorem)
16 + 4 - 2 + 2k = 0
20 - 2 + 2k = 0
18 + 2k = 0
2k = -18
k = -18/2
k = -9
thus the value of k is (-9)
x = (-4)
(-4)square - (-4) - 2 + 2k = 0 (By factor theorem)
16 + 4 - 2 + 2k = 0
20 - 2 + 2k = 0
18 + 2k = 0
2k = -18
k = -18/2
k = -9
thus the value of k is (-9)
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