Question

If -4 is the zero of the polynomial p(x) = x^2 + 11x + K, Find the value of K

Answer 1

-4 is zero of polynomial p(x)= x^2+11x+k So we can put x=-4 in equation P(4)= (-4^2)+11×-4+k 0= 16-44+k K= 28

Answer 2

Given :

P(x) = x²+11x+k

To Find:

Value of k

Solution :

Given that -4 is the zero of polynomial p(x)

Putting x = -4

p(x) = x²+11x+k

p(-4) = (-4)²+11(-4)+k

16-44+k = 0

-28+k = 0

k = 28