If -4 is the zero of the polynomial p(x) = x² +11x + k, then find the value of k.
Answers
Answered by
35
p(x)=x² + 11x + K
To find the value of K
Here,
Thus,
p(-4)=(-4)²+11(-4)+K
=16-44+K
=K-28
By Remainder Theorm,
Any polynomial,p(x) is always equal to zero
Thus,
K-28=0
→K=28
Answered by
11
Step-by-step explanation:
Hi,
(-4) is the one zero of the given polynomial x² +11x + k .
Therefore,
X = (-4)
Putting the value of x in x² + 11x + k .
P( x ) = 0
P(4) = (-4)² + 11 × -4 + k
=> 16 - 44 + k = 0
=> -28 + k = 0
=> k = 28
Hope it will help you :)
Similar questions